export function countPairsWithDiffK(numbers: number[], k: number): number {
  // Escribe tu solución aquí
  let count = 0;


  if(k === 0) return 1;
  

  for(let i = 0; i < numbers.length; i++) {
    for(let j = 0; j < numbers.length; j++) {
      if(numbers[i] - numbers[j] === k ) {
        count += 1
      }
    }
  }


  return count;
}