export function groupConsecutiveDuplicates(nums: number[]): number[][] {
  // Escribe tu solución aquí

  const consecutiveNumbersGroups=[];
  let previousNumber = NaN;

  nums.forEach((current, index)=>{
    if(current !== previousNumber){
      consecutiveNumbersGroups.push([current])
      previousNumber = current;
    }else if(current == previousNumber){
        consecutiveNumbersGroups[consecutiveNumbersGroups.length - 1].push(current)
      
    }

  });

  return consecutiveNumbersGroups;

  
}