Solución
solution.tsTypeScript
def group_consecutive_duplicates(nums: list[int]) -> list[list[int]]:
n = len(nums)
count, results = 1, []
for i in range(n):
if i < n-1 and nums[i] == nums[i+1]:
count += 1
else:
results.append([nums[i]]*count)
count = 1
return results0respuestas