Solución
solution.tsTypeScript
def group_anagrams(words: list[str]) -> list[list[str]]:
# Escribe tu solución aquí
final = []
for word in words:
flag = False
for ins in final:
if "".join(sorted(ins[0])) == "".join(sorted(word)):
ins.append(word)
flag = True
ins.sort()
if not flag:
final.append([word])
def orden(datos):
return datos[0]
new = sorted(final, key=orden)
return new0respuestas